B. Organic Chemistry · Organic ChemistryReactions of Hydrocarbons: Combustion, Substitution and Addition
B3.3 B2.4 B2.2 A1.4 A1.10About 75 minutes
Learning goals- I can write balanced equations for complete and incomplete combustion of hydrocarbons.
- I can describe substitution reactions of alkanes and of benzene.
- I can predict the products of addition reactions of alkenes and alkynes (H₂, halogens, hydrogen halides and water), using Markovnikov's rule.
- I can describe how bromine water or potassium permanganate distinguishes saturated, unsaturated and aromatic hydrocarbons, and the safety precautions involved.
Words to know
combustion
A rapid reaction with oxygen that releases energy; complete combustion of a hydrocarbon gives CO₂ and H₂O.
substitution reaction
A reaction in which an atom or group on a molecule is replaced by another atom or group.
addition reaction
A reaction in which atoms add across a double or triple bond, which becomes a single (or double) bond; there is one product.
hydrogenation
Addition of H₂ to a multiple bond, using a metal catalyst such as Pt, Pd or Ni.
halogenation
Adding a halogen (Cl₂, Br₂) to a molecule, by addition (alkenes) or substitution (alkanes, benzene).
hydration
Addition of water (H and OH) across a C=C bond to make an alcohol, using an acid catalyst.
Markovnikov's rule
When HX or H₂O adds to an unsymmetrical alkene, the H goes to the double-bond carbon that already has more H atoms.
WHMIS
Workplace Hazardous Materials Information System: Canada's system of hazard pictograms, labels and safety data sheets (SDS).
What hydrocarbons do
Alkanes are sometimes called paraffins, from Latin words meaning "little affinity", because they react with very little at room temperature. Alkenes and alkynes are far more reactive: their double and triple bonds are rich in electrons and easy to attack. This lesson covers the four big reaction types of hydrocarbons:
- Combustion (all hydrocarbons)
- Substitution (alkanes and aromatics)
- Addition (alkenes and alkynes)
- Tests that use these differences to identify an unknown
Remember from Grade 11: in Chemical Reactions you balanced combustion equations and compared complete and incomplete combustion. We start there.
1. Combustion
Complete combustion (plenty of oxygen) gives carbon dioxide and water:
C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
Incomplete combustion (limited oxygen) also gives carbon monoxide (CO) and soot (C):
2 CH₄ + 3 O₂ → 2 CO + 4 H₂O
Carbon monoxide is colourless, odourless and deadly, because it binds to hemoglobin in place of oxygen. That is why Ontario law requires carbon monoxide alarms in homes with a fuel-burning appliance, a fireplace or an attached garage, and why you should never run a generator, barbecue or car in a closed space.
Worked exampleExample 1: Balancing complete combustion
Write the balanced equation for the complete combustion of octane, C₈H₁₈.
- Unbalanced: C₈H₁₈ + O₂ → CO₂ + H₂O.
- Balance C: 8 CO₂. Balance H: 18 H → 9 H₂O.
- Count O on the right: 16 + 9 = 25 O atoms, so 12.5 O₂.
- Double everything to clear the fraction.
2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O
2. Substitution
Alkanes react with chlorine or bromine only when energy is supplied as ultraviolet light (or high heat). One H atom is replaced by a halogen atom, and the H leaves with the other halogen atom as HX:
CH₄ + Cl₂ —(UV light)→ CH₃Cl + HCl
The reaction does not stop neatly. CH₃Cl can react again to give CH₂Cl₂, CHCl₃ and CCl₄, and larger alkanes give mixtures of position isomers, so this is a messy way to make one pure product.
Benzene also undergoes substitution, not addition, because addition would destroy its stable ring of delocalized electrons. It needs a catalyst such as FeBr₃:
C₆H₆ + Br₂ —(FeBr₃)→ C₆H₅Br + HBr
How to recognize a substitution: two reactants → two products, and one of the products is usually a small molecule such as HCl or HBr.
3. Addition to alkenes and alkynes
In an addition reaction, the double bond opens and one new atom bonds to each carbon of the former double bond. Two reactants → one product. The four main additions are:
- Hydrogenation, H₂: metal catalyst (Pt, Pd or Ni) → alkane. CH₂=CH₂ + H₂ → CH₃CH₃
- Halogenation, Br₂ or Cl₂: room temperature → dihaloalkane. CH₂=CH₂ + Br₂ → CH₂BrCH₂Br
- Hydrohalogenation, HCl or HBr: → haloalkane. CH₂=CH₂ + HBr → CH₃CH₂Br
- Hydration, H₂O: acid catalyst (H₂SO₄) → alcohol. CH₂=CH₂ + H₂O → CH₃CH₂OH (This is how much industrial ethanol is made.)
An alkyne can add twice: the triple bond becomes a double bond, then a single bond.
HC≡CH + 2 H₂ —(Pt)→ CH₃CH₃
Addition of bromine to ethene. The two carbons of the double bond each gain one bromine atom, and the double bond becomes a single bond. Two reactants make one product.Markovnikov's rule
When H–Br adds to a symmetrical alkene such as ethene or but-2-ene, there is only one possible product. But propene is unsymmetrical: the H could go to C1 or to C2. Experiments show that one product strongly dominates. The Russian chemist Vladimir Markovnikov summarized the pattern in 1869:
When HX or H–OH adds to an unsymmetrical alkene, the H atom goes to the double-bond carbon that already has more H atoms, and the X (or OH) goes to the other carbon.
So propene + HBr gives mainly 2-bromopropane, and propene + H₂O gives mainly propan-2-ol. In university organic chemistry you will learn the reason: the reaction passes through a positively charged intermediate, and a positive charge on the more substituted carbon is more stable.
Markovnikov's rule for propene + HBr. C1 already has two H atoms and C2 has one, so the new H goes to C1 and the Br to C2. The main product is 2-bromopropane.Worked exampleExample 2: Predicting addition products
Give the structure and name of the main product: (a) but-2-ene + H₂ (Ni); (b) propene + HCl; (c) 2-methylpropene + H₂O (H₂SO₄ catalyst).
- (a) Symmetrical; each C of the double bond gains an H: CH₃CH₂CH₂CH₃, butane.
- (b) CH₂=CH–CH₃: C1 has 2 H, C2 has 1 H. H goes to C1, Cl to C2: CH₃CHClCH₃, 2-chloropropane.
- (c) CH₂=C(CH₃)₂: C1 has 2 H, C2 has none. H goes to C1, OH to C2: (CH₃)₃COH, 2-methylpropan-2-ol.
(a) butane, (b) 2-chloropropane, (c) 2-methylpropan-2-ol.
Worked exampleExample 3: An alkyne adds twice
Write the equation for but-1-yne reacting with excess bromine. Name the product.
- HC≡C–CH₂CH₃ has a triple bond, so it can add two Br₂ molecules.
- Each carbon of the triple bond ends up with two Br atoms.
- Product: CHBr₂–CBr₂–CH₂CH₃.
HC≡CCH₂CH₃ + 2 Br₂ → CHBr₂CBr₂CH₂CH₃, 1,1,2,2-tetrabromobutane.
Worked exampleExample 4: Substitution or addition?
Classify each: (a) C₂H₆ + Br₂ → C₂H₅Br + HBr (UV light); (b) C₃H₆ + Br₂ → C₃H₆Br₂; (c) C₆H₆ + Cl₂ → C₆H₅Cl + HCl (FeCl₃).
- (a) Two products, an H replaced by Br, HBr formed → substitution (alkane).
- (b) One product containing all the atoms of both reactants → addition (alkene).
- (c) Two products, ring H replaced by Cl → substitution (aromatic).
(a) substitution, (b) addition, (c) substitution.
4. Testing for unsaturation: a lab you can describe
In a school lab, a few drops of a hydrocarbon are added to bromine water, which is orange-brown.
- An alkene or alkyne decolourizes it immediately: the Br₂ adds across the multiple bond and is used up.
- An alkane gives no change in the dark. (In bright sunlight it slowly reacts by substitution.)
- Benzene gives no change: without a catalyst, it does not react.
Potassium permanganate solution is another test: an alkene turns the purple solution brown (a brown precipitate of MnO₂ forms), while alkanes and benzene leave it purple.
Safety (A1.4): bromine water is toxic and corrosive, and its vapour irritates the lungs. The test is done in a fume hood, with safety goggles, gloves and a lab coat. Hydrocarbons such as hexane and cyclohexene are flammable: no open flames in the room. Check the WHMIS label and the safety data sheet (SDS) for each chemical before you begin, and pour all organic waste into the labelled waste container, never down the sink. Do not try this test at home.
Results of the bromine-water test. Only the unsaturated hydrocarbon (an alkene) removes the orange-brown colour at once; the alkane and benzene do not react under these conditions.Addition in your kitchen: hydrogenation and trans fats
Vegetable oils are liquids because their long carbon chains contain cis C=C bonds, which put kinks in the chains so they cannot pack closely. Adding H₂ with a nickel catalyst (hydrogenation) converts some C=C bonds to C–C bonds, so the chains straighten and the fat becomes solid, like shortening or hard margarine.
Partial hydrogenation has a side effect: some of the remaining double bonds flip from cis to trans. Trans fats raise the risk of heart disease, so Canada banned partially hydrogenated oils in foods in September 2018. This is a real example of B1: understanding an organic reaction helped shape a public health law.
Hands-on activityWatching combustion with a candle
You need: a tea light or short candle in a holder, a metal spoon, a clear glass jar (heat-resistant, such as a canning jar), a plate, matches or a lighter, and a grown-up. Grown-up note: an adult should light the candle and stay for the whole activity. Work on a non-flammable surface, tie back long hair, keep a damp cloth nearby, and let the spoon and jar cool before touching them.
- Light the candle. Candle wax is a mixture of large alkanes (paraffin, about C₂₀ to C₄₀).
- Using an oven mitt, hold the back of the cold spoon in the tip of the flame for 3 seconds. Look at the spoon. What is the black deposit?
- Hold the cold, dry jar upside down about 10 cm above the flame for 5 seconds. Look inside it.
- Place the jar over the candle on the plate. Time how long the flame lasts.
- Write a word equation and a balanced equation for complete combustion of C₂₅H₅₂, a typical wax alkane.
What to look for: the spoon collects soot (carbon): incomplete combustion where the spoon cools the flame and blocks oxygen. The jar fogs with water, a product of combustion. Under the jar the flame goes out once the oxygen is used up. Balanced equation: C₂₅H₅₂ + 38 O₂ → 25 CO₂ + 26 H₂O.
Just for funStudents often remember Markovnikov's rule as "the rich get richer": the carbon that is already rich in hydrogen atoms gets the new one. It is the only time chemists approve of hydrogen hoarding.
Your turn
1Balance the complete combustion of ethane, C₂H₆.
2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O.
2What two products of incomplete combustion are not formed in complete combustion?
Carbon monoxide (CO) and carbon (soot).
3Complete: CH₃CH₃ + Cl₂ —(UV)→ ? + ?. Name the organic product and the reaction type.
CH₃CH₂Cl + HCl; chloroethane; substitution.
4Give the product of propene + H₂ (Pt catalyst).
propane, CH₃CH₂CH₃ (addition, hydrogenation).
5Give the main product of but-1-ene + HBr.
CH₂=CHCH₂CH₃: H to C1 (2 H), Br to C2: 2-bromobutane, CH₃CHBrCH₂CH₃.
6Name the product of cyclohexene + Br₂.
7A liquid decolourizes bromine water immediately. What does that tell you?
It is unsaturated: it contains a C=C or C≡C bond (an alkene or alkyne).
More practice: warm-up
1What are the products of the complete combustion of any hydrocarbon?
2What type of reaction turns an alkene into an alkane?
Addition of H₂ (hydrogenation).
3What catalyst is used in hydrogenation?
A metal such as Pt, Pd or Ni.
4What does an alkane need to react with Cl₂?
5Which kind of hydrocarbon undergoes substitution with Br₂ only when FeBr₃ is present?
An aromatic hydrocarbon such as benzene.
More practice: on your own
1Predict the main product of hydration of propene and name it.
H to C1, OH to C2: propan-2-ol (2-propanol), CH₃CH(OH)CH₃.
2Write a balanced equation for incomplete combustion of propane that produces CO and H₂O only.
2 C₃H₈ + 7 O₂ → 6 CO + 8 H₂O. (Check: O on the right = 6 + 8 = 14 = 7 × 2 ✓)
3Which alkene would you start with to make 2-chlorobutane by addition of HCl, so that only one product is possible?
but-2-ene, CH₃CH=CHCH₃: it is symmetrical, so H and Cl can add only one way. (But-1-ene would give mainly 2-chlorobutane too, but with some 1-chlorobutane.)
4How many moles of H₂ can one mole of buta-1,3-diene add? Name the final product.
Two C=C bonds → 2 mol H₂; product butane.
5Explain why benzene does not decolourize bromine water, even though its formula suggests three double bonds.
Benzene's six electrons are delocalized around the ring, giving it extra stability. Adding Br₂ would destroy this stable ring, so benzene does not react by addition; it only reacts by substitution, and only with a catalyst such as FeBr₃.
Challenge
1A hydrocarbon X, C₅H₁₀, decolourizes bromine water. Hydrogenation of X gives 2-methylbutane. Applying Markovnikov's rule, hydration of X is predicted to give 3-methylbutan-2-ol, CH₃CH(OH)CH(CH₃)₂, as the main product. Identify X.
X must be an alkene with the 2-methylbutane skeleton: 2-methylbut-1-ene, 2-methylbut-2-ene or 3-methylbut-1-ene. Apply Markovnikov's rule to each. 2-methylbut-1-ene and 2-methylbut-2-ene both put the OH on C2 (the carbon with the methyl and no H), giving 2-methylbutan-2-ol. 3-methylbut-1-ene, CH₂=CHCH(CH₃)₂, adds H to C1 (2 H) and OH to C2, giving CH₃CH(OH)CH(CH₃)₂ = 3-methylbutan-2-ol. So X is 3-methylbut-1-ene. (In a real lab, the positive intermediate of this reaction can rearrange and give other alcohols too, which you will study in university; in this course, apply Markovnikov's rule directly.)
2Bromine water test: 2.00 g of a sample of cyclohexene (C₆H₁₀, 82.14 g/mol) is mixed with excess bromine. What mass of Br₂ (159.80 g/mol) reacts?
n(C₆H₁₀) = 2.00 ÷ 82.14 = 0.024349 mol. One C=C adds one Br₂, so n(Br₂) = 0.024349 mol. Mass = 0.024349 × 159.80 = 3.89 g.
3A student proposes making pure 2-chlorobutane by reacting butane with Cl₂ in UV light. Evaluate the plan and suggest a better one.
Poor plan: free-radical substitution of butane gives a mixture of 1-chlorobutane and 2-chlorobutane, plus dichloro and polychloro products, which are hard to separate. Better: add HCl to but-2-ene (symmetrical, so only 2-chlorobutane forms) by an addition reaction.
Check your understandingQuiz
1. Which equation shows an addition reaction?
2. What is the main product when HCl adds to propene?
3. Which compound decolourizes bromine water immediately at room temperature?
4. What condition is needed for methane to react with chlorine?
5. Which product forms in incomplete but NOT in complete combustion?
6. Why did Canada ban partially hydrogenated oils in 2018?
7. Which safety step is essential when doing the bromine-water test?
For parents and teachersBig ideas (B3.3, B2.4): alkanes burn and undergo substitution (with UV light); alkenes and alkynes undergo addition; benzene undergoes substitution with a catalyst. Markovnikov's rule predicts the main product when HX or water adds to an unsymmetrical alkene.
How to help: Ask your teen to sort reactions by counting: "two reactants → one product" is addition; "two → two, with HX" is substitution. Ask them to explain the bromine-water results.
Common difficulties:
- Putting the H on the wrong carbon (Markovnikov's rule).
- Writing alkanes undergoing addition (they have no multiple bond).
- Forgetting that alkynes can add two molecules.
- Fractions in combustion equations: double all coefficients.
Safety: the candle activity needs an adult present the whole time. The bromine-water and permanganate tests are school-lab procedures only. Make sure your home has a working carbon monoxide alarm.