B. Organic Chemistry · Organic ChemistryAldehydes and Ketones: The Carbonyl Group and Oxidizing Alcohols
B2.2 B2.4 B3.1 B3.2 B3.3 A1.4 A1.5About 75 minutes
Learning goals- I can recognize, name and draw aldehydes and ketones.
- I can compare the boiling points and solubility of aldehydes and ketones with alkanes and alcohols.
- I can predict the products of oxidizing primary, secondary and tertiary alcohols.
- I can describe a safe investigation that distinguishes 1°, 2° and 3° alcohols by oxidation.
Words to know
carbonyl group
A carbon atom double-bonded to an oxygen atom, C=O.
aldehyde
A compound with a carbonyl group at the end of a chain, bonded to at least one H: –CHO.
ketone
A compound with a carbonyl group bonded to two carbon atoms: R–CO–R′.
oxidation (organic)
A reaction in which a carbon compound gains O atoms or loses H atoms.
reduction (organic)
A reaction in which a carbon compound gains H atoms or loses O atoms.
oxidizing agent
A substance that causes oxidation, such as acidified potassium dichromate or potassium permanganate; shown as [O] in organic equations.
Smells of the kitchen
Open a jar of cinnamon, a bottle of vanilla or a bottle of almond extract. The main flavour molecules are cinnamaldehyde, vanillin and benzaldehyde, and all three are aldehydes. Nail polish remover is mostly acetone, a ketone. Both families contain the carbonyl group, C=O.
- In an aldehyde, the carbonyl carbon is at the end of a chain, bonded to at least one H. It is written –CHO (not –COH).
- In a ketone, the carbonyl carbon is inside the chain, bonded to two carbons: R–CO–R′.
An aldehyde and a ketone with the same number of carbons are functional-group isomers: propanal and propanone are both C₃H₆O.
The carbonyl group (highlighted) is at the end of the chain in an aldehyde and in the middle of the chain in a ketone.Naming aldehydes and ketones
Aldehydes: replace the -e of the alkane with -al: methanal (HCHO), ethanal (CH₃CHO), propanal, butanal. The aldehyde carbon is always C1, so it needs no number. Branches are numbered from the CHO end: (CH₃)₂CHCH₂CHO is 3-methylbutanal.
Ketones: replace -e with -one and give the carbonyl carbon the lowest possible number: CH₃COCH₂CH₂CH₃ is pentan-2-one (2-pentanone) and CH₃CH₂COCH₂CH₃ is pentan-3-one. Propanone and butanone need no number: the C=O can only be on C2. A ketone needs at least three carbons.
Common names you will meet: formaldehyde (methanal), acetaldehyde (ethanal), acetone (propanone) and methyl ethyl ketone, or MEK (butanone), a solvent in some glues and paints.
Worked exampleExample 1: Naming carbonyl compounds
Name (a) CH₃CH₂CH₂CHO, (b) CH₃COCH₂CH₃, (c) CH₃CH₂CH(CH₃)CH₂CHO, (d) CH₃CH₂CH₂COCH₃.
- (a) 4 C ending in –CHO: butanal.
- (b) 4 C with C=O on C2: butanone (butan-2-one).
- (c) 5 C chain; number from the CHO carbon: C1 = CHO, C2 = CH₂, C3 = CH(CH₃). 3-methylpentanal.
- (d) 5 C; number from the right so the C=O is on C2 (from the left it would be C4): pentan-2-one.
(a) butanal, (b) butanone, (c) 3-methylpentanal, (d) pentan-2-one.
Properties
- The C=O bond is very polar, so aldehydes and ketones have dipole-dipole forces. Their boiling points are higher than those of alkanes of similar mass.
- They have no O–H, so they cannot hydrogen-bond to each other. Their boiling points are lower than those of alcohols of similar mass.
Compare molecules of almost the same mass: butane (58 g/mol) −1 °C; propanal (58 g/mol) 48 °C; propanone (58 g/mol) 56 °C; propan-1-ol (60 g/mol) 97 °C.
- The carbonyl O can accept hydrogen bonds from water, so small aldehydes and ketones dissolve well: methanal, ethanal and propanone mix with water in all proportions; butanone dissolves to about 27 g per 100 mL. Solubility falls as the chain grows.
- Many have strong odours. Small aldehydes smell sharp; larger ones often smell fruity or flowery and are used in perfumes and flavours.
- Methanal (formaldehyde) is a gas sold dissolved in water as formalin, used to preserve biological specimens and to make resins in plywood and particleboard. It is a known human carcinogen, which is why building products in Canada have limits on how much formaldehyde they can release.
Making aldehydes and ketones: oxidizing alcohols
In organic chemistry, oxidation means a carbon compound gains O or loses H. Common oxidizing agents are acidified potassium dichromate (K₂Cr₂O₇ with H₂SO₄) and potassium permanganate (KMnO₄). In equations they are often written as [O].
To be oxidized, the carbon that holds the –OH must have at least one H to lose. So:
- Primary alcohol → aldehyde → carboxylic acid. The aldehyde forms first. If it stays in the flask with more oxidizing agent, it is oxidized again to a carboxylic acid (Lesson 10). To stop at the aldehyde, chemists distil it out as soon as it forms (aldehydes boil lower than their alcohols).
- Secondary alcohol → ketone. Ketones resist further oxidation.
- Tertiary alcohol → no reaction. The C–OH carbon has no H.
CH₃CH₂OH + [O] → CH₃CHO + H₂O
CH₃CH(OH)CH₃ + [O] → CH₃COCH₃ + H₂O
The reverse, adding H₂ to a C=O with a metal catalyst, is a reduction: aldehydes are reduced to primary alcohols and ketones to secondary alcohols.
Your body uses the same chemistry: liver enzymes oxidize ethanol to ethanal and then to ethanoic acid. Ethanal is toxic, which is one reason drinking alcohol harms the body.
Oxidation of alcohols. A primary alcohol is oxidized to an aldehyde and then to a carboxylic acid; a secondary alcohol to a ketone; a tertiary alcohol does not react, because its C–OH carbon has no H to lose.Worked exampleExample 2: Predicting oxidation products
Predict the product(s) of oxidizing (a) butan-1-ol, (b) pentan-3-ol, (c) 2-methylbutan-2-ol with excess acidified dichromate.
- (a) CH₃CH₂CH₂CH₂OH is primary → butanal → with excess oxidizing agent, butanoic acid (CH₃CH₂CH₂COOH).
- (b) CH₃CH₂CH(OH)CH₂CH₃ is secondary → pentan-3-one (CH₃CH₂COCH₂CH₃).
- (c) CH₃CH₂C(CH₃)(OH)CH₃ is tertiary → no reaction; the solution stays orange.
(a) butanoic acid (via butanal), (b) pentan-3-one, (c) no reaction.
Worked exampleExample 3: Planning a synthesis
Which alcohol would you oxidize to make (a) pentan-2-one, (b) 2-methylpropanal?
- (a) A ketone comes from a secondary alcohol with the –OH where the C=O will be: pentan-2-ol, CH₃CH(OH)CH₂CH₂CH₃.
- (b) An aldehyde comes from a primary alcohol with the same skeleton: (CH₃)₂CHCH₂OH, 2-methylpropan-1-ol, distilling off the aldehyde as it forms.
(a) pentan-2-ol, (b) 2-methylpropan-1-ol.
Investigation: telling 1°, 2° and 3° alcohols apart (lab only)
Question: Can oxidation with acidified dichromate distinguish primary, secondary and tertiary alcohols?
Hypothesis: Primary and secondary alcohols will be oxidized (orange → green); the tertiary alcohol will not.
Method (in a school lab):
- Put 2 mL of acidified potassium dichromate solution in each of three labelled test tubes.
- Add 5 drops of propan-1-ol, propan-2-ol or 2-methylpropan-2-ol.
- Warm the tubes in a hot-water bath (about 60 °C) for 5 minutes. No open flames: the alcohols are flammable.
- Record colour changes. Carefully waft to compare odours (the aldehyde from propan-1-ol has a sharp smell).
Variables: independent: type of alcohol; dependent: colour change; controlled: volumes, temperature, time.
Safety (A1.4): potassium dichromate contains chromium(VI): it is toxic, a carcinogen and a strong oxidizer, and the solution contains sulfuric acid. Wear goggles, gloves and a lab coat; work in a fume hood; collect all chromium waste in the labelled heavy-metal container. Many schools use acidified potassium permanganate instead (purple → colourless with 1° and 2° alcohols).
Expected results of the dichromate test. The orange Cr₂O₇²⁻ ion is reduced to green Cr³⁺ only when the alcohol is oxidized, so the primary and secondary alcohols turn the solution green and the tertiary alcohol does not.Hands-on activityThe waft lab: identifying aldehydes by smell (safely)
You need: small amounts of ground cinnamon, pure vanilla extract and pure almond extract (from the baking aisle), three small cups labelled A, B and C, a family member to set them up, and paper. Grown-up note: these are food flavourings and safe to smell. The extracts contain alcohol: don't let young children drink them. Never smell any lab chemical directly; this activity practises the safe way.
- Ask a family member to put one flavouring in each cup without telling you which is which.
- Practise wafting: hold the cup about 20 cm from your face and gently sweep the air above it toward your nose with your hand. Never put your nose over the cup.
- Identify A, B and C. Record your confidence (sure / guess).
- Look up the structures of cinnamaldehyde, vanillin and benzaldehyde (for example on PubChem). Circle the –CHO group on each. What other functional groups does vanillin have?
- If you have acetone nail polish remover, with a grown-up and in a ventilated room away from flames, waft it as well and compare: a ketone, with a very different smell.
What to look for: all three flavour molecules contain a benzene ring and a –CHO group. Vanillin also has an –OH on the ring (a phenol group) and an –OCH₃ (an ether group). Wafting lets you notice a smell without breathing in a large dose: the technique you will use with every lab chemical.
Just for funCinnamaldehyde, vanillin and benzaldehyde are all aldehydes, so a batch of cinnamon-almond-vanilla cookies is basically a delicious aldehyde convention.
Your turn
methanal (formaldehyde) and ethanal (acetaldehyde).
butanone (butan-2-one, methyl ethyl ketone).
3Draw (condensed) hexan-3-one.
4Why can't a ketone have only two carbon atoms?
The carbonyl carbon of a ketone must be bonded to two other carbons, so at least three carbons are needed (propanone).
5What is the product of oxidizing propan-2-ol?
propanone (acetone), CH₃COCH₃.
6Rank by boiling point: propanone, propan-2-ol, butane.
butane (−1 °C) < propanone (56 °C) < propan-2-ol (82 °C): London only; dipole-dipole; hydrogen bonding.
7Why doesn't 2-methylpropan-2-ol react with acidified dichromate?
It is a tertiary alcohol: the carbon bonded to –OH has no H atom to lose, so it cannot form a C=O.
More practice: warm-up
1What is the functional group of aldehydes and ketones?
2What ending does an aldehyde name have?
3What ending does a ketone name have?
4What is the common name of propanone?
5What colour change shows that acidified dichromate has oxidized an alcohol?
More practice: on your own
Number the chain from the CHO carbon: CHO is C1, CH₂ is C2, CH is C3, and one of the two CH₃ groups continues the chain as C4; the other CH₃ is a branch on C3. 3-methylbutanal.
4-carbon chain with C=O; number from the right: C1 = CH₃, C2 = C=O, C3 = CH(CH₃), C4 = CH₃. 3-methylbutan-2-one (3-methylbutanone).
3Write the two-step oxidation of propan-1-ol with names.
CH₃CH₂CH₂OH + [O] → CH₃CH₂CHO (propanal) + H₂O; CH₃CH₂CHO + [O] → CH₃CH₂COOH (propanoic acid).
4Propanal (bp 48 °C) is made by oxidizing propan-1-ol (bp 97 °C). How can a chemist collect propanal before it is oxidized further?
Heat the mixture above 48 °C but below 97 °C and distil the propanal off as it forms, so it leaves the flask before it meets more oxidizing agent. The alcohol stays behind.
5Explain why propanone dissolves in water in any proportion, even though it cannot hydrogen-bond to itself.
Its polar C=O oxygen has lone pairs that accept hydrogen bonds from water's H atoms, and the molecule is small (only two CH₃ groups), so it mixes completely.
Challenge
1An unknown alcohol C₄H₁₀O turns acidified dichromate green, and the organic product is a ketone. Identify the alcohol and the ketone.
A ketone comes from a secondary alcohol. The only secondary C₄ alcohol is butan-2-ol, CH₃CH(OH)CH₂CH₃. The product is butanone, CH₃COCH₂CH₃.
2In acid, the half-reaction for dichromate is Cr₂O₇²⁻ + 14 H⁺ + 6 e⁻ → 2 Cr³⁺ + 7 H₂O, and for ethanol → ethanal it is C₂H₅OH → CH₃CHO + 2 H⁺ + 2 e⁻. Combine them into a balanced overall equation.
Multiply the ethanol half-reaction by 3 to give 6 e⁻: 3 C₂H₅OH → 3 CH₃CHO + 6 H⁺ + 6 e⁻. Add and cancel 6 e⁻ and 6 H⁺: Cr₂O₇²⁻ + 8 H⁺ + 3 C₂H₅OH → 2 Cr³⁺ + 3 CH₃CHO + 7 H₂O. (You will study balancing like this in the unit Electrochemistry.)
3Design a test to tell propanal from propanone, using the idea of oxidation. Predict the results.
Warm each with acidified dichromate (or another mild oxidizing agent). Propanal has an H on its carbonyl carbon, so it is oxidized to propanoic acid: the solution turns green. Propanone has no H on its carbonyl carbon and resists oxidation: the solution stays orange. Controls: same volumes, temperature and time; a blank tube with water.
Check your understandingQuiz
1. Which structure is an aldehyde?
2. What is the IUPAC name of CH₃COCH₂CH₂CH₃?
3. What is formed when a secondary alcohol is oxidized?
4. Which alcohol does NOT change the colour of acidified dichromate?
5. Why is the boiling point of propanone (56 °C) lower than that of propan-1-ol (97 °C)?
6. What is the safe way to smell a substance in the lab?
For parents and teachersBig ideas (B2.2, B3.3, B2.4): the carbonyl group C=O defines aldehydes (–CHO, ending -al) and ketones (R–CO–R′, ending -one). Oxidizing a primary alcohol gives an aldehyde and then a carboxylic acid; a secondary alcohol gives a ketone; a tertiary alcohol does not react.
How to help: Ask your teen to draw the alcohol, aldehyde and acid with the same carbon skeleton (for example propan-1-ol, propanal, propanoic acid) and explain each oxidation step.
Common difficulties:
- Writing aldehydes as –COH instead of –CHO.
- Numbering aldehydes (the CHO carbon is always C1).
- Predicting that tertiary alcohols oxidize.
- Forgetting that a primary alcohol can go past the aldehyde to the acid.
Safety: the smell activity uses food flavourings only. Potassium dichromate is a carcinogen: the oxidation test is a supervised lab procedure, never a home experiment.