Grade by Grade
B. Organic Chemistry · Organic Chemistry

Esters: Esterification and Hydrolysis

B2.2 B2.4 B3.2 B3.3 A1.4 A1.5About 75 minutes
Learning goals
  • I can name and draw esters and identify the acid and alcohol they come from.
  • I can write equations for esterification (a condensation reaction) and for acid and base hydrolysis of esters.
  • I can explain the physical properties of esters, including their smells and boiling points.
  • I can describe a safe esterification investigation and explain how soap is made by saponification.

Words to know

ester
A compound with the group –COO– linking two carbon groups: R–COO–R′.
esterification
The condensation reaction of a carboxylic acid with an alcohol to form an ester and water, catalysed by an acid.
hydrolysis
A reaction in which water (often with an acid or base) splits a molecule into two parts; the reverse of a condensation.
saponification
Hydrolysis of an ester, especially a fat, with a strong base such as NaOH, producing an alcohol and a carboxylate salt (soap).
triglyceride
A fat or oil molecule: an ester of glycerol (propane-1,2,3-triol) with three fatty acids.
reflux
Heating a reaction mixture with a vertical condenser so that vapours condense and drip back, allowing long heating without losing volatile substances.

Chemistry you can smell

Peel a banana, sniff a pineapple or chew wintergreen gum. Much of what you smell is an ester: banana's sweet note comes largely from 3-methylbutyl ethanoate, pineapple's from ethyl butanoate, and wintergreen from methyl salicylate. Esters are also in nail polish, solvents, fats and oils, and the polyester in your clothing.

An ester has the group –COO– between two carbon groups: R–COO–R′. It looks like a carboxylic acid whose acidic H has been replaced by a carbon group. In fact, that is how esters are made: from a carboxylic acid and an alcohol.

Esterification

When a carboxylic acid is heated with an alcohol and a few drops of concentrated sulfuric acid (the catalyst), they join and lose a water molecule:

carboxylic acid + alcohol ⇌ ester + water

CH₃COOH + CH₃CH₂OH ⇌ CH₃COOCH₂CH₃ + H₂O

  • It is a condensation reaction: two molecules join and a small molecule (water) is released.
  • The OH comes from the acid and the H from the alcohol. Chemists proved this by making the alcohol with a heavy oxygen isotope, ¹⁸O: the ¹⁸O ended up in the ester, not in the water.
  • The reaction is reversible and reaches equilibrium (you will study this in the unit Chemical Equilibrium). Using excess alcohol, or removing water, increases the yield of ester.
  • In the lab, the mixture is often heated under reflux so the volatile reactants and products don't escape.
CH₃COOHethanoic acid+HOCH₂CH₃ethanolH₂SO₄,heatthe OH from the acid and the H from the alcohol leave as waterCH₃COOCH₂CH₃+ H₂Ofrom the acidfrom the alcoholethyl ethanoate (an ester)
Esterification of ethanoic acid with ethanol. The highlighted OH of the acid and H of the alcohol leave as water, and a new C–O bond joins the two pieces.

Naming esters

An ester's name has two words, like the name of a salt:

  1. First word: the alcohol part, named as an alkyl group: methyl, ethyl, propyl...
  2. Second word: the acid part, with -oic acid changed to -oate: methanoate, ethanoate, propanoate...

To tell the parts apart, find the C=O. The carbon chain that includes the C=O carbon came from the acid. The group bonded to the single-bonded O came from the alcohol.

Watch out: chemists often write the acid part first in the formula, CH₃COOCH₂CH₃, but say the alcohol part first in the name, ethyl ethanoate. The formula can also be written the other way round: CH₃CH₂OOCCH₃ is the same compound.

Common names use the common acid names: ethyl ethanoate is ethyl acetate, a solvent in some nail polish removers and glues.

CH₃CH₂COOCH₃acid part (has the C=O)propanoic acid → propanoatealcohol partmethanol → methylname: alcohol part firstmethyl propanoateCH₃CH₂COOCH₃
Naming an ester. The part with the C=O comes from the acid (propanoic acid → propanoate). The part on the other side of the single-bonded O comes from the alcohol (methanol → methyl). Say the alcohol part first: methyl propanoate.
Worked example

Example 1: Naming esters

Name (a) HCOOCH₂CH₃, (b) CH₃CH₂CH₂COOCH₃, (c) CH₃COOCH₂CH₂CH(CH₃)₂.

  1. (a) Acid part: HCOO– (1 C, methanoate). Alcohol part: –CH₂CH₃ (ethyl). ethyl methanoate.
  2. (b) Acid part: CH₃CH₂CH₂COO– (4 C, butanoate). Alcohol part: –CH₃ (methyl). methyl butanoate.
  3. (c) Acid part: CH₃COO– (ethanoate). Alcohol part: –CH₂CH₂CH(CH₃)₂, a 4-carbon chain numbered from the carbon attached to O, with a methyl on C3: 3-methylbutyl.

(a) ethyl methanoate, (b) methyl butanoate, (c) 3-methylbutyl ethanoate (the banana ester).

Worked example

Example 2: Predicting an esterification

Write the equation for the reaction of butanoic acid with ethanol. Name the ester.

  1. Acid: CH₃CH₂CH₂COOH. Alcohol: CH₃CH₂OH.
  2. Remove OH from the acid and H from the alcohol; join the pieces with the alcohol's O.
  3. CH₃CH₂CH₂COOH + HOCH₂CH₃ ⇌ CH₃CH₂CH₂COOCH₂CH₃ + H₂O.

The product is ethyl butanoate, which smells of pineapple.

Worked example

Example 3: Working backwards

Which acid and alcohol would you use to make propyl ethanoate (a pear-scented ester)?

  1. ethanoate → the acid is ethanoic acid, CH₃COOH.
  2. propyl → the alcohol is propan-1-ol, CH₃CH₂CH₂OH.
  3. Equation: CH₃COOH + CH₃CH₂CH₂OH ⇌ CH₃COOCH₂CH₂CH₃ + H₂O (H₂SO₄ catalyst).

ethanoic acid and propan-1-ol.

Properties of esters

  • Esters are polar (two C–O bonds and a C=O), but they have no O–H, so they cannot hydrogen-bond to each other. Their boiling points are lower than those of acids and alcohols of similar mass, and higher than those of alkanes: ethyl ethanoate (88 g/mol) boils at 77 °C, while butanoic acid (88 g/mol) boils at 164 °C.
  • Their oxygens can accept hydrogen bonds from water, so small esters are slightly soluble: about 8 g of ethyl ethanoate dissolves in 100 mL of water.
  • Many small esters are volatile with fruity or flowery smells. Food scientists blend them to make artificial flavours.

Bigger esters you know:

  • Fats and oils are triglycerides: esters of glycerol with three long-chain fatty acids.
  • ASA (acetylsalicylic acid, sold as aspirin) is an ester made from salicylic acid. Many peoples, including First Nations in North America, have long used willow bark to relieve pain; it contains salicin, which the body converts to salicylic acid. Chemists later made ASA, which is gentler on the stomach.
  • Polyesters such as PET (water bottles and fleece) contain thousands of ester links (Lesson 15).

Hydrolysis: splitting esters

Acid hydrolysis is the reverse of esterification. Heating an ester with water and an acid catalyst gives back the acid and the alcohol:

CH₃COOCH₂CH₃ + H₂O ⇌ CH₃COOH + CH₃CH₂OH

Base hydrolysis (saponification) uses a strong base such as NaOH. It goes to completion, because the acid formed is immediately turned into its salt:

CH₃COOCH₂CH₃ + NaOH → CH₃COONa + CH₃CH₂OH

Making soap. Heating a fat with sodium hydroxide hydrolyses all three ester links, giving glycerol and three sodium salts of fatty acids: soap. A soap ion has a long non-polar tail, which dissolves in grease, and an ionic head (–COO⁻), which dissolves in water, so soap lifts grease off your hands and into the rinse water.

a fat (triglyceride)C–O–C(=O)–C–O–C(=O)–C–O–C(=O)–3 ester links to glycerol+ 3 NaOHheatglycerolC–OHC–OHC–OH+3 soap ions (with Na⁺)–COO⁻ Na⁺–COO⁻ Na⁺–COO⁻ Na⁺non-polar tail, ionic head
Saponification. Sodium hydroxide breaks the three ester links of a fat, giving glycerol and three soap ions. Each soap ion has a long non-polar tail and an ionic –COO⁻ head.
Worked example

Example 4: Hydrolysis products

Give the products of (a) acid hydrolysis and (b) base hydrolysis (NaOH) of methyl propanoate.

  1. Methyl propanoate: CH₃CH₂COOCH₃ (acid part propanoate, alcohol part methyl).
  2. (a) Acid hydrolysis gives back the acid and the alcohol: CH₃CH₂COOH + CH₃OH.
  3. (b) Base hydrolysis gives the salt of the acid and the alcohol: CH₃CH₂COONa + CH₃OH.

(a) propanoic acid + methanol; (b) sodium propanoate + methanol.

Investigation: making esters (school lab only)

Purpose: to prepare several esters and relate their smells to their structures (B2.4).

Procedure outline:

  1. In a test tube, mix 10 drops of a carboxylic acid (for example ethanoic acid) with 10 drops of an alcohol (for example 3-methylbutan-1-ol, ethanol or octan-1-ol).
  2. Your teacher adds 2 drops of concentrated sulfuric acid.
  3. Warm the tube in a hot-water bath (about 60 °C, heated on a hot plate) for 10 to 15 minutes.
  4. Pour the mixture into a small beaker of cool sodium hydrogen carbonate solution, which neutralizes the leftover acids and lets the ester float as an oily layer.
  5. Waft to identify the smell.

Safety (A1.4): concentrated sulfuric acid is highly corrosive: goggles, gloves and lab coat; your teacher dispenses it. Alcohols and esters are flammable: no open flames; use a hot plate. Work in a well-ventilated room or fume hood. Never taste anything, and dispose of organic waste in the labelled container.

Variables (A1.5): the acid and alcohol (independent); the smell (dependent); volumes, temperature and time (controlled). Smell is a subjective observation, so have several people record it independently.

Hands-on activity

The great flavour sniff-off

You need: a ripe banana, some fresh or canned pineapple, banana-flavoured candy, wintergreen-flavoured gum or candies, a notebook. Grown-up note: use foods and candies only; do not use pure oil of wintergreen (it is concentrated methyl salicylate and is toxic if swallowed).

  1. Smell the real banana and the banana candy. Do they smell the same? Describe the difference.
  2. Smell the pineapple. Then smell the wintergreen gum.
  3. Draw the esters responsible: 3-methylbutyl ethanoate (banana), ethyl butanoate (pineapple) and methyl salicylate (wintergreen). For each one, circle the –COO– group and name the acid and alcohol that would make it. (Methyl salicylate comes from salicylic acid and methanol.)
  4. Read the candy label. Does it list "artificial flavour"? Explain why a company might use a single synthetic ester instead of real fruit.

What to look for: the candy smells simpler and stronger. Real fruit contains hundreds of volatile compounds, including many esters, while artificial flavours use one or a few esters. Banana: ethanoic acid + 3-methylbutan-1-ol. Pineapple: butanoic acid + ethanol.

Just for fun

The ester family that makes bananas and pineapples smell sweet also makes polyester shirts. Luckily your shirt doesn't smell like fruit salad: in a polymer, the ester links are locked into huge chains that are far too big to evaporate into your nose.

Your turn

1

Name CH₃COOCH₃.

2

Name CH₃CH₂COOCH₂CH₂CH₃.

3

Write the condensed formula of ethyl methanoate.

4

Which acid and alcohol make butyl ethanoate?

5

Write the equation for methanol + propanoic acid.

6

What are the products of saponifying ethyl ethanoate with NaOH?

7

Why does ethyl ethanoate boil lower than butanoic acid, its isomer?

More practice: warm-up

1

What functional group do esters have?

2

What two kinds of compounds react to form an ester?

3

What small molecule is released in esterification?

4

What catalyst is used in esterification?

5

What is saponification?

More practice: on your own

1

Name CH₃CH₂CH₂COOCH₂CH₂CH₂CH₂CH₃ and give its acid and alcohol.

2

Draw (condensed) octyl ethanoate (the smell of oranges) and give its molecular formula.

3

Explain why using excess ethanol increases the yield of ethyl ethanoate.

4

Why is sodium hydrogen carbonate solution added at the end of the ester lab?

5

Ethyl ethanoate and butanoic acid are both C₄H₈O₂. What kind of isomers are they?

Challenge

1

6.00 g of ethanoic acid (60.06 g/mol) reacts with excess ethanol. 5.28 g of ethyl ethanoate (88.11 g/mol) is collected. Find the percentage yield and give two reasons it is below 100%.

2

ASA is made by reacting the –OH of salicylic acid (2-hydroxybenzoic acid) with ethanoic acid (industrially, with a more reactive relative). Which functional group of salicylic acid becomes an ester, and which stays?

3

Soap works poorly in hard water, which contains Ca²⁺ ions. Suggest why, using solubility, and explain why synthetic detergents were developed.

Check your understanding

Quiz

1.

What is the name of CH₃CH₂COOCH₂CH₃?

2.

Which pair of reactants forms methyl ethanoate?

3.

What type of reaction is esterification?

4.

What are the products of the saponification of an ester with NaOH?

5.

Why do esters have lower boiling points than carboxylic acids of similar mass?

6.

Which safety step is required when concentrated sulfuric acid is used in the ester lab?

For parents and teachers

Big ideas (B2.2, B3.3, B2.4): esters (R–COO–R′) form when a carboxylic acid and an alcohol condense, losing water. They are named alkyl alkanoate, alcohol part first. Hydrolysis reverses the reaction; base hydrolysis of fats makes soap.

How to help: Write an ester formula and ask your teen to cover the part with the C=O and name each half. Ask which acid and alcohol they would use to make a given ester.

Common difficulties:

  • Naming the acid part first ("ethanoate ethyl") or mixing up which side is which.
  • Forgetting the water product in esterification.
  • Thinking base hydrolysis gives the free acid (it gives its salt).

Safety: the ester synthesis uses concentrated sulfuric acid and flammable liquids and is a school-lab procedure only. At home, use foods and candies for the smell activity, not essential oils.