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B. Biochemistry · Biochemistry

How Enzymes Work: Active Sites, Activation Energy and Cofactors

B3.4 B2.1 A1.12 A1.13About 75 minutes
Learning goals
  • I can describe enzymes as protein catalysts with an active site formed by specific R groups.
  • I can use an energy diagram to explain how an enzyme lowers activation energy without changing ΔG.
  • I can describe the induced-fit model and four ways an active site speeds up a reaction.
  • I can explain the roles of cofactors, coenzymes and prosthetic groups, and interpret a rate versus substrate concentration graph.

Words to know

enzyme
A biological catalyst, usually a protein, that speeds up a specific reaction by lowering its activation energy, without being used up.
activation energy (Eₐ)
The energy needed to start a reaction by reaching the unstable transition state.
active site
The pocket or groove on an enzyme where the substrate binds and the reaction takes place. Its shape and chemistry come from particular R groups.
substrate
The molecule an enzyme acts on.
enzyme-substrate complex
The temporary combination of enzyme and substrate held in the active site by weak bonds.
induced fit
The model in which substrate binding causes the active site to change shape slightly so it grips the substrate more closely.
cofactor
A non-protein helper an enzyme needs to work: an inorganic ion (such as Zn²⁺, Mg²⁺, Fe²⁺) or an organic molecule called a coenzyme.
coenzyme
An organic cofactor, often made from a vitamin, such as NAD⁺ (from niacin) or coenzyme A.
turnover number
The number of substrate molecules one enzyme molecule converts to product per second when it is working at full speed.

A million times a second

Every time you breathe out, your red blood cells release CO₂ that was carried as bicarbonate ions. The reaction H₂CO₃ ⇌ CO₂ + H₂O happens on its own, but far too slowly for life. The enzyme carbonic anhydrase speeds it up enormously: one molecule of the enzyme can handle on the order of a million molecules per second.

Almost every reaction in a cell has its own enzyme. In Grade 11 you learned what enzymes do. This lesson is about how they do it, at the level of molecules and energy.

Remember from Grade 11

SBI3U introduced enzymes as catalysts that lower activation energy, the active site, substrate, the induced-fit model (and the older lock-and-key model), specificity, the -ase naming pattern, and the effects of temperature, pH and concentration. Here we go deeper into structure, energy diagrams, mechanisms and cofactors.

Enzymes are (mostly) folded proteins

An enzyme's active site is a small region, often a cleft or pocket, formed where the polypeptide folds bring particular R groups together. Those R groups do two jobs:

  • some bind the substrate (by hydrogen bonds, ionic bonds and hydrophobic interactions), which gives the enzyme its specificity;
  • others catalyze: they take part in the chemistry of breaking or forming bonds.

Because the active site depends on tertiary (and sometimes quaternary) structure, anything that denatures the enzyme destroys the site. (A few catalysts in cells are RNA molecules, called ribozymes; the part of the ribosome that forms peptide bonds is one.)

Enzymes are usually named after their substrate or reaction plus -ase: sucrase, lipase, DNA polymerase, lactate dehydrogenase (removes H, a redox reaction). The international system sorts enzymes into main classes by reaction type, including oxidoreductases (redox), transferases (move a group), hydrolases (hydrolysis), lyases, isomerases and ligases (join molecules using ATP).

Lowering activation energy

Even a reaction that releases energy (negative ΔG) needs an input of activation energy to reach the transition state, an unstable arrangement in which old bonds are partly broken and new ones partly formed. At body temperature, few molecules have enough energy, so the uncatalyzed reaction is slow.

An enzyme provides a different pathway with a lower activation energy. Look at the energy diagram:

  • The enzyme lowers Eₐ, so many more molecules can react each second.
  • It does not change the energies of the reactants or products, so ΔG is the same. An enzyme cannot make an energy-requiring reaction happen on its own (that needs coupling to ATP, which you'll meet in Metabolic Processes).
  • It speeds up the forward and reverse reactions equally, so it does not change where the equilibrium lies; it only helps the reaction reach equilibrium faster.
  • The enzyme comes out unchanged and can be used again and again.
progress of reactionfree energyreactantsproductsEₐ without enzymeEₐ with enzymeΔG (sameeither way)no enzymewith enzyme
An exergonic reaction with and without an enzyme. The enzyme lowers the activation energy (Eₐ) but the reactants, products and ΔG stay the same.

Induced fit and the catalytic cycle

  1. The substrate binds to the active site, forming the enzyme-substrate complex.
  2. Binding causes the enzyme to change shape slightly (induced fit), wrapping the active site around the substrate.
  3. The reaction happens; the complex becomes an enzyme-product complex.
  4. The products are released, and the enzyme returns to its original shape, ready for the next substrate.

Four ways an active site lowers Eₐ

  • Orientation: it holds two substrates close together in exactly the right position to react, instead of waiting for a lucky collision.
  • Strain: induced fit stretches or bends bonds in the substrate toward the transition state, making them easier to break.
  • Microenvironment: the active site can provide conditions different from the surrounding solution, such as a pocket of acidic R groups that donate H⁺ or a non-polar pocket.
  • Direct participation: R groups (or a cofactor) may briefly form covalent bonds with the substrate, or pass electrons or protons to it, then return to their original state.
enzyme + substrateenzyme-substrate complexenzyme-product complexenzyme + productsenzymesubstrateactive site opensite closes(induced fit)bond brokenenzyme unchanged,ready againproducts
The catalytic cycle. Substrate binding changes the shape of the active site (induced fit), the substrate is converted to products, and the enzyme is released unchanged. Simplified shapes.

Cofactors and coenzymes

Many enzymes need a non-protein partner, a cofactor:

  • Inorganic ions: carbonic anhydrase holds a zinc ion (Zn²⁺) in its active site; many enzymes that use ATP need Mg²⁺; catalase contains iron in a heme group.
  • Coenzymes are organic cofactors, many made from vitamins: NAD⁺ from niacin (vitamin B₃), FAD from riboflavin (vitamin B₂), and coenzyme A from pantothenic acid (vitamin B₅). They often carry electrons or chemical groups from one enzyme to another. This is one reason a lack of certain vitamins harms so many body functions.
  • A cofactor bound very tightly, even permanently, is called a prosthetic group (such as the heme in catalase).

An enzyme without its cofactor is an inactive apoenzyme; with it, it is a holoenzyme.

How fast? Rate and substrate concentration

If you keep the amount of enzyme constant and increase the substrate concentration, the rate rises at first, because enzymes and substrates meet more often. Eventually every active site is busy almost all the time: the enzyme is saturated and the rate levels off at a maximum, Vmax. The substrate concentration that gives half of Vmax is called Km. A low Km means the enzyme reaches half speed at low substrate concentration: it binds its substrate tightly (high affinity).

The turnover number tells how many substrate molecules one enzyme molecule handles per second at Vmax: from a few per second for some enzymes to around a million for carbonic anhydrase.

0481216200255075100substrate concentration (mmol/L)rate (µmol/min)Vmax = 100½Vmax at [S] = 2 (= Km)rate rises steeply at firstlevels off: active sites saturated
A typical rate vs substrate concentration curve for a fixed amount of enzyme. The rate rises, then levels off at Vmax when active sites are saturated. Here Km, the substrate concentration giving half of Vmax, is 2 mmol/L.
Worked example

Example: Reading enzyme graphs

(a) In the energy diagram for a reaction, the reactants are at 60 kJ/mol, the products at 20 kJ/mol, the uncatalyzed transition state at 140 kJ/mol and the catalyzed transition state at 90 kJ/mol (values relative to an arbitrary zero). Find Eₐ with and without the enzyme, and ΔG. (b) Use the rate curve above: what is the rate at a substrate concentration of 2 mmol/L, and what happens to Vmax if you double the amount of enzyme?

  1. (a) Eₐ (no enzyme) = 140 − 60 = 80 kJ/mol.
  2. Eₐ (enzyme) = 90 − 60 = 30 kJ/mol. The enzyme lowered Eₐ by 50 kJ/mol.
  3. ΔG = products − reactants = 20 − 60 = −40 kJ/mol in both cases (exergonic).
  4. (b) At 2 mmol/L the rate is half of Vmax = 50 µmol/min (this point defines Km).
  5. Vmax is reached when all active sites are busy. Doubling the enzyme doubles the number of active sites, so Vmax doubles to 200 µmol/min. (Km, a property of the enzyme and substrate, stays the same.)

(a) 80 kJ/mol without, 30 kJ/mol with; ΔG = −40 kJ/mol either way. (b) 50 µmol/min; Vmax doubles to 200 µmol/min.

Just for fun

Carbonic anhydrase can deal with around a million molecules a second. If it worked as a grocery-store cashier, the line would vanish before you found your wallet.

Hands-on activity

Paper-ase: model enzyme saturation

You need: a stack of scrap paper cut into about 120 strips (about 2 cm × 10 cm), a table, a timer (phone), a partner, and graph paper or a spreadsheet.

You are the enzyme. Each strip is a substrate molecule. "Catalysis" = tearing a strip in half and dropping both halves (products) in a pile.

  1. Spread 5 strips randomly over the whole table. With your eyes on the table, use one hand to pick up a strip, tear it, drop it, and reach for the next one. Your partner times 15 seconds and counts how many you tear. Put any untorn strips back.
  2. Repeat with 10, 20, 40 and 80 strips spread over the same area. Do each trial twice and average.
  3. Graph rate (strips torn per 15 s) against number of strips on the table (substrate concentration).
  4. Mark your Vmax (the level where the curve flattens) and estimate your "Km" (the number of strips that gave half of Vmax).
  5. Bonus: add a second person as "enzyme" (doubling enzyme concentration) at 80 strips. What happens to the rate?

What to look for: at low substrate numbers, much of your time is spent finding a strip, so the rate rises steeply as you add strips. At high numbers there is always a strip in reach, and the limit is how fast your hand can tear: the curve levels off (saturation). Two "enzymes" roughly double the maximum rate. Report your averages with sensible precision (whole numbers of strips) (A1.13).

Your turn

1

How does an enzyme speed up a reaction?

2

Does an enzyme change ΔG for a reaction? Explain.

3

Describe the induced-fit model.

4

Give two ways an active site lowers activation energy.

5

What is the difference between a cofactor and a coenzyme?

6

Why does the reaction rate level off at high substrate concentration?

More practice: warm-up

1

What is a substrate?

2

Which vitamin is used to make NAD⁺?

3

What metal ion is in the active site of carbonic anhydrase?

4

What does the ending "-ase" usually tell you?

5

Is an enzyme used up in a reaction?

More practice: on your own

1

In an energy diagram, the reactants are at 50 kJ/mol, the products at 85 kJ/mol, and the catalyzed transition state at 110 kJ/mol. Find Eₐ (catalyzed) and ΔG, and say whether the reaction is exergonic or endergonic.

2

Enzyme A has a Km of 0.1 mmol/L for its substrate; enzyme B has a Km of 5 mmol/L for the same substrate. Which binds the substrate more tightly? Explain.

3

Explain why a mutation that changes one amino acid far from the active site can still stop an enzyme from working.

4

A person's diet is very low in riboflavin (vitamin B₂). Predict a cellular effect.

5

Why does an enzyme speed up both the forward and reverse reactions?

Challenge

1

Carbonic anhydrase has a turnover number of about 1 × 10⁶ s⁻¹. How many CO₂ molecules could 1 × 10⁻¹² mol of the enzyme process in one minute at Vmax? (Avogadro's number = 6.02 × 10²³ mol⁻¹)

2

Explain, using the four mechanisms, why an enzyme that binds its transition state more tightly than its substrate is a better catalyst.

3

Two students argue: "Enzymes make reactions happen that otherwise couldn't happen." vs "Enzymes only make reactions happen faster." Who is right? Use ΔG and equilibrium in your answer.

Check your understanding

Quiz

1.

An enzyme speeds up a reaction by:

2.

Which is a coenzyme?

3.

In the induced-fit model:

4.

At very high substrate concentrations, adding more substrate does not increase the rate because:

5.

If the amount of enzyme is doubled (with plenty of substrate), Vmax will:

6.

A low Km means an enzyme:

For parents and teachers

Big idea: This lesson covers B3.4 (the chemical structures and mechanisms of enzymes) and B2.1 vocabulary (substrate, substrate-enzyme complex). The paper-tearing model practises graphing and reporting data (A1.12, A1.13).

How to help: Ask your teen to sketch the energy diagram from memory and label Eₐ (with and without enzyme) and ΔG. Then ask, "Does the enzyme change ΔG? Why not?" The Paper-ase activity needs a partner with a timer, which is a great job for a parent or sibling.

Common difficulties:

  • Thinking enzymes "add energy" or change ΔG. They only lower the barrier.
  • Confusing Vmax (depends on how much enzyme) with Km (a property of the enzyme and substrate, which doesn't change with enzyme amount).
  • Mixing up cofactor (any non-protein helper) and coenzyme (organic cofactor).