B. Matter, Chemical Trends, and Chemical Bonding · Matter, Chemical Trends, and Chemical BondingIonization Energy and Electron Affinity
B2.1 B3.3 B2.2 A1.6About 70 minutes
Learning goals- I can define first ionization energy and electron affinity and write equations for them.
- I can describe and explain the trends in ionization energy and electron affinity.
- I can use successive ionization energies to find the number of valence electrons.
- I can use these properties to explain why metals form cations and non-metals form anions.
Words to know
ionization energy
The energy needed to remove an electron from one mole of gaseous atoms or ions.
first ionization energy (IE₁)
The energy needed to remove the most loosely held electron from one mole of gaseous atoms.
successive ionization energies
The energies needed to remove the 1st, 2nd, 3rd... electrons one after another.
electron affinity
The energy change when one mole of gaseous atoms gains one mole of electrons; for most elements energy is released.
kJ/mol
Kilojoules per mole, the unit for energy per mole of atoms.
reactivity
How readily a substance takes part in chemical reactions.
Which atoms give up electrons easily?
Drop a small piece of sodium into water (a teacher demonstration only, behind a safety shield) and it fizzes, melts into a ball and races around the surface. Potassium does the same thing even more violently. Neon, in a glowing sign, does not react with anything at all.
These differences come down to one question: how much energy does it take to pull an electron off an atom? That quantity, ionization energy, can be measured very precisely, and its pattern across the periodic table is one of the clearest pieces of evidence that electrons are arranged in shells.
Ionization energy
The first ionization energy (IE₁) is the energy needed to remove the most loosely held electron from one mole of atoms in the gas state:
X(g) + energy → X⁺(g) + e⁻
It is measured in kilojoules per mole (kJ/mol). (A mole is a counting unit for very large numbers of particles; you will use it a lot in the Quantities in Chemical Reactions unit.) A high ionization energy means the electron is held tightly. A low ionization energy means it comes off easily.
Trends:
- Across a period, IE₁ generally increases. Zeff increases and the atoms get smaller, so valence electrons are held more tightly.
- Down a group, IE₁ decreases. The valence electrons are in shells farther from the nucleus, with more shielding, so they are easier to remove.
The noble gases have the highest values in each period (helium has the highest of all, 2372 kJ/mol) and the alkali metals the lowest. That is why metals on the left form positive ions so easily and the noble gases hardly react.
First ionization energies of the first 20 elements. Peaks are noble gases; the lowest points are the alkali metals Li, Na and K. The pattern repeats each period, just as the periodic law says.Small dips: B after Be, O after N
Look closely at the graph. Boron's IE₁ (801 kJ/mol) is a little lower than beryllium's (899), and oxygen's (1314) is a little lower than nitrogen's (1402). The same dips appear in period 3 (Al after Mg, S after P). These small exceptions are real data, not errors. They are explained by the way electrons are arranged in sub-shells (orbitals) within each shell, which you will study in Grade 12 Chemistry (SCH4U). For now, notice that the general trend across the period still holds.
Successive ionization energies
After one electron is removed, a second and third can be removed too, but each needs more energy, because the remaining electrons are held by the same protons with less electron repulsion.
The really useful clue is a huge jump. For magnesium (2, 8, 2), the 1st and 2nd ionization energies are fairly low (738 and 1451 kJ/mol), but the 3rd is 7733 kJ/mol, more than five times the 2nd. The third electron must come from the core (shell 2), much closer to the nucleus and not shielded by any other shell. The jump tells you magnesium has 2 valence electrons, which is exactly why magnesium forms Mg²⁺ and never Mg³⁺.
Magnesium's first two electrons are valence electrons. The third is a core electron, so the energy needed jumps by a factor of more than five.Electron affinity
The electron affinity of an element is the energy change when one mole of gaseous atoms gains one mole of electrons:
X(g) + e⁻ → X⁻(g)
For most elements, energy is released when an electron is added, because the electron is attracted by the nucleus. The more energy released, the more strongly the atom attracts an extra electron. (Some data tables write released energy as a negative number, such as −349 kJ/mol for chlorine. In this lesson we give the amount of energy released as a positive number and say "released".)
Trends (general, with more exceptions than ionization energy):
- Across a period, more energy is generally released, reaching a maximum at the halogens (group 17). A halogen needs only one electron to complete its outer shell, and its large Zeff pulls that electron in strongly.
- Down a group, less energy is generally released, because the added electron goes into a shell farther from the nucleus. (Fluorine is an exception: it releases a little less than chlorine, because its very small outer shell is crowded and the electrons repel the newcomer.)
- The noble gases do not form stable negative ions: an added electron would have to start a new shell, far from the nucleus.
| Element | First ionization energy (kJ/mol) | Energy released on gaining an electron (kJ/mol) |
|---|
| Na | 496 | 53 |
| Mg | 738 | does not form a stable ion |
| Si | 787 | 134 |
| S | 1000 | 200 |
| Cl | 1251 | 349 |
| Ar | 1521 | does not form a stable ion |
| F | 1681 | 328 |
| Br | 1140 | 325 |
| I | 1008 | 295 |
Ionization energy and electron affinity data (rounded).Putting it together: metals and non-metals
- Metals (left side) have low ionization energies and small electron affinities. They lose electrons easily and form cations.
- Non-metals (right side, except noble gases) have high ionization energies and large electron affinities. They gain electrons and form anions.
- Reactivity: for metals, the lower the ionization energy, the more reactive the metal. That is why reactivity increases down group 1 (Li < Na < K). For halogens, reactivity decreases down the group (F > Cl > Br > I), because larger atoms attract electrons less strongly.
Worked exampleExample 1: Predicting ionization energy order
Arrange Al, Cl, Na and Ar in order of increasing first ionization energy. Explain.
- All four are in period 3, so the general trend (IE₁ increases across a period) applies.
- Na is in group 1, Al in group 13, Cl in group 17, Ar in group 18.
- Check with data: Na 496, Al 578, Cl 1251, Ar 1521 kJ/mol.
Na < Al < Cl < Ar. Zeff increases across the period, so valence electrons are held more tightly.
Worked exampleExample 2: Reading successive ionization energies
An element in period 3 has these ionization energies (kJ/mol): IE₁ = 578, IE₂ = 1817, IE₃ = 2745, IE₄ = 11 577. Identify the element.
- Look for the big jump: from IE₃ (2745) to IE₄ (11 577), the energy more than quadruples.
- So the first three electrons are valence electrons and the fourth comes from the core.
- A period 3 element with 3 valence electrons is in group 13.
The element is aluminium (2, 8, 3), which forms Al³⁺.
Worked exampleExample 3: Explaining a reactivity trend
Potassium reacts with water more vigorously than sodium. Use ionization energy to explain.
- Reactions of alkali metals involve losing the single valence electron.
- K (419 kJ/mol) has a lower IE₁ than Na (496 kJ/mol) because its valence electron is in shell 4, farther from the nucleus and more shielded.
- Less energy needed to remove the electron means the reaction starts and proceeds more easily.
Potassium is more reactive because its valence electron is easier to remove (lower ionization energy).
Just for funHelium has the highest first ionization energy of any element: 2372 kJ/mol. When it comes to its two electrons, helium simply does not let go. Clingiest element on the table.
Hands-on activityGraph the ionization energy pattern by hand
You need: graph paper (or a spreadsheet), a ruler, a pencil and two coloured pencils.
- Draw axes: atomic number 1 to 20 across, first ionization energy 0 to 2500 kJ/mol up (1 square = 100 kJ/mol works well).
- Plot the 20 values: H 1312, He 2372, Li 520, Be 899, B 801, C 1086, N 1402, O 1314, F 1681, Ne 2081, Na 496, Mg 738, Al 578, Si 787, P 1012, S 1000, Cl 1251, Ar 1521, K 419, Ca 590. Join the points.
- Colour the noble gases in one colour and the alkali metals in another.
- Answer: (a) Where do the peaks fall? (b) Where are the lowest points? (c) How many elements are there from one peak to the next? (d) Mark the two small dips in each period.
What to look for: peaks at 2, 10, 18 (He, Ne, Ar), lowest points at 3, 11, 19 (Li, Na, K), 8 elements between peaks after the first period, and dips at B, O, Al and S. You have just found evidence for electron shells, the same way scientists did.
Your turn
1Write the equation for the first ionization of calcium.
Ca(g) → Ca⁺(g) + e⁻ (energy is absorbed).
2Which has the higher first ionization energy, and why: (a) Li or Cs? (b) C or O?
(a) Li: its valence electron is much closer to the nucleus. (b) O: larger Zeff in the same shell (1314 vs 1086 kJ/mol).
3An element has IE₁ = 496, IE₂ = 4562 kJ/mol. How many valence electrons does it have? Name it if it is in period 3.
The big jump is after the first electron: 1 valence electron. Period 3, group 1: sodium.
4Why do halogens release a lot of energy when they gain an electron?
They are one electron short of a full shell, and their large Zeff (+7) attracts the added electron strongly.
5Explain why argon does not form Ar⁻.
An added electron would have to go into a new shell (shell 4), far from the nucleus and well shielded, so it is not held.
6Rank the halogens F, Cl, Br, I in order of reactivity, and explain.
F > Cl > Br > I. Smaller halogens attract an extra electron more strongly, so they react more readily.
More practice: warm-up
1Define first ionization energy.
The energy needed to remove the most loosely held electron from one mole of gaseous atoms.
2Which group has the lowest ionization energies?
3Which element has the highest first ionization energy of all?
4Do metals tend to gain or lose electrons?
Lose them (low ionization energy), forming cations.
5What is the unit for ionization energy in this lesson?
More practice: on your own
1The IE₁ values of Be (899) and B (801) break the general trend. State the general trend and say where students will learn the explanation.
IE₁ generally increases across a period. The dip is explained by sub-shells (orbitals) in Grade 12 Chemistry (SCH4U).
2Why is the second ionization energy of sodium (4562 kJ/mol) about 9 times its first (496 kJ/mol)?
The second electron comes from the core (shell 2): closer to the nucleus, not shielded by another shell, and removed from an ion that is already positive.
3Predict which forms a 2+ ion more easily, Ca or Mg, and justify.
Ca: its valence electrons are in shell 4, farther away, so its ionization energies are lower.
4A data table lists the electron affinity of chlorine as −349 kJ/mol. What does the negative sign mean?
Energy is released (349 kJ/mol) when chlorine atoms gain electrons.
5Use ionization energy and electron affinity to explain why sodium and chlorine form Na⁺ and Cl⁻, not Na⁻ and Cl⁺.
Sodium has a low IE (easy to lose its 1 valence electron) and little attraction for extra electrons. Chlorine has a high IE (hard to remove electrons) and a large electron affinity (strongly attracts one more electron).
Challenge
1An unknown period 3 element has IE₁ to IE₄ = 787, 1577, 3232 and 4356 kJ/mol, and IE₅ = 16 091 kJ/mol. Identify it and explain.
The big jump is between IE₄ and IE₅ (about 3.7 times), so it has 4 valence electrons: group 14, period 3 = silicon.
2The first ionization energy of hydrogen is 1312 kJ/mol, about 2.5 times that of lithium (520). Both have one valence electron. Explain the difference.
Hydrogen's electron is in shell 1, very close to the nucleus with no shielding (Zeff = +1 with no core). Lithium's valence electron is in shell 2, farther away and shielded by 2 core electrons.
3Fluorine releases 328 kJ/mol when it gains an electron, slightly less than chlorine (349). Does this contradict the idea that fluorine is the most reactive halogen? Explain.
No. Electron affinity is only one factor. Fluorine is very small, so its outer shell is crowded and repels the extra electron a little, lowering its electron affinity. But fluorine's bond with itself (F–F) is weak and its small ions form very strong bonds with other atoms, so overall its reactions release more energy and it is still the most reactive. Trends describe general patterns; individual values can have exceptions.
Check your understandingQuiz
1. Which equation represents the first ionization energy of magnesium?
2. Which element has the lowest first ionization energy?
3. An element has successive ionization energies 900, 1757, 14 849 and 21 007 kJ/mol. How many valence electrons does it have?
4. Which group of elements releases the most energy when gaining an electron?
5. Reactivity of the alkali metals increases down the group because
6. Which statement about the noble gases is correct?
For parents and teachersBig idea: Ionization energy and electron affinity are two of the terms in expectation B2.1, and explaining their trends is part of B3.3. Low ionization energy means an atom loses electrons easily (metals); large electron affinity means it gains them readily (non-metals, especially halogens).
How to help: Graphing the 20 ionization energies by hand is worth the time: the peaks and troughs make the shell model feel real. Ask, "Where are the peaks? Why there?"
Common difficulties:
- Confusing ionization energy (removing an electron) with electron affinity (adding one).
- Sign conventions: some tables show electron affinity as negative numbers (energy released). Help your teen read the heading of any table carefully.
- Treating every small exception (B, O, Al, S) as a mistake. Science trends describe the general pattern; the exceptions are explained in Grade 12.
- Forgetting to look for the biggest jump, not just any increase, in successive ionization energies.