C. Structure and Properties of Matter · Structure and Properties of MatterElectron Configuration and the Periodic Table: Blocks, Properties and Trends
C3.3 C2.2 A1.8About 70 minutes
Learning goals- I can identify the s, p, d and f blocks and relate each to the sublevel being filled.
- I can read condensed electron configurations directly from an element's position in the table.
- I can describe characteristic properties of the elements in each block.
- I can use sublevels and electron pairing to explain trends and exceptions in ionization energy.
Words to know
s, p, d, f blocks
Regions of the periodic table named for the sublevel that receives the last electron.
transition metals
d-block elements; many form ions of several charges, coloured compounds and catalysts.
lanthanides / actinides
The f-block series in which 4f / 5f orbitals are filling.
effective nuclear charge (Zeff)
The net positive charge felt by a valence electron after shielding by inner electrons.
successive ionization energies
The energies needed to remove the first, second, third ... electrons from an atom, one after another.
The periodic table is an electron-configuration chart
Mendeleev arranged the elements by their properties in 1869, long before anyone knew about electrons. The quantum mechanical model explains why his arrangement works: elements in the same group have the same valence configuration, and the shape of the table follows the sublevels.
Remember from Grade 11: in SCH3U you explained the trends in atomic radius, ionization energy, electron affinity and electronegativity using effective nuclear charge (Zeff) and the distance of valence electrons from the nucleus. You also saw small "exceptions" in ionization energy that were promised an explanation in Grade 12. Here it is.
The four blocks
- s block (groups 1 and 2, plus helium): the last electron enters an ns orbital. Valence configuration ns¹ or ns².
- p block (groups 13 to 18): the last electron enters an np orbital. Valence configuration ns² np¹ to ns² np⁶.
- d block (groups 3 to 12, the transition metals): the last electron enters an (n − 1)d orbital. Period 4 transition metals fill 3d.
- f block (the lanthanides and actinides, usually printed below the table): the last electron enters an (n − 2)f orbital.
The widths of the blocks match the sublevel capacities: 2, 6, 10 and 14. Period lengths (2, 8, 8, 18, 18, 32, 32) follow from which sublevels fill in each period. You can read a configuration straight off the table: walk across the periods to the element, writing each block you pass. For example, selenium (period 4, fourth p column) is [Ar] 4s² 3d¹⁰ 4p⁴.
The periodic table drawn by blocks (period numbers at the left). The block tells you which sublevel the last electron enters: s (2 columns), p (6), d (10) and f (14). Helium sits above group 18 but has an s² configuration.Characteristic properties of each block
s block: soft, reactive metals with low ionization energies. They lose their one or two valence electrons easily to form 1+ (group 1) or 2+ (group 2) ions. Group 1 metals react vigorously with water. (Hydrogen, though placed above group 1 because it is 1s¹, is a non-metal.)
p block: the most varied block. It contains metals (aluminium, tin, lead), metalloids (silicon, germanium) along a staircase line, non-metals (carbon, nitrogen, oxygen, the halogens) and the noble gases, whose full ns² np⁶ configuration makes them very unreactive. Non-metals here tend to gain electrons (forming anions such as Cl⁻ and O²⁻) or share them.
d block (transition metals): hard, dense metals with high melting points (except mercury). Because 4s and 3d electrons are close in energy, many form ions with several different charges (iron: 2+ and 3+; copper: 1+ and 2+; manganese: from 2+ up to 7+). Many of their compounds are coloured (copper(II) sulfate solution is blue) and many are paramagnetic because of unpaired d electrons. Many are good catalysts (iron in ammonia manufacture, platinum and palladium in car catalytic converters).
f block: the lanthanides are very similar to one another chemically (their differences are buried in the inner 4f sublevel), which makes them hard to separate. Some are used in strong magnets, such as neodymium magnets in wind turbines, electric motors and earbuds. The actinides are all radioactive; uranium and plutonium are nuclear fuels.
Explaining the trends with sublevels
The general trends from Grade 11 still hold: across a period, Zeff increases, so atoms get smaller and ionization energy (IE) and electronegativity increase; down a group, valence electrons are in higher n levels, farther from the nucleus, so atoms get larger and IE decreases.
Now look at the period 2 ionization energies in the graph. There are two dips:
- Be → B (899 → 801 kJ/mol). Boron's outermost electron is in a 2p orbital, which is higher in energy than 2s and partly shielded by the 2s electrons. It is easier to remove, even though boron's nuclear charge is higher.
- N → O (1402 → 1314 kJ/mol). Nitrogen's three 2p electrons are each alone in an orbital. Oxygen's fourth 2p electron must pair with another in the same orbital. The extra electron-electron repulsion in that orbital makes it easier to remove.
The same two dips appear in period 3 (Mg → Al and P → S).
First ionization energies across period 2 (data in kJ/mol). The general rise comes from increasing effective nuclear charge; the two dips at boron and oxygen are explained by sublevels.Successive ionization energies show the shells
Removing electrons one after another takes more energy each time, but there is a huge jump when you start removing core electrons from a full inner level. For magnesium ([Ne] 3s²):
- IE₁ = 738 kJ/mol, IE₂ = 1451 kJ/mol, then IE₃ = 7733 kJ/mol.
The jump after the second electron shows magnesium has 2 valence electrons, which is why it forms Mg²⁺ and never Mg³⁺. Successive ionization energies are some of the strongest experimental evidence that electrons are arranged in levels.
Worked exampleExample 1: Reading a configuration from the table
Use the block layout to write the condensed configuration of arsenic (period 4, group 15) and of tungsten (period 6, group 6).
- Arsenic: the core is [Ar]. In period 4 you pass 4s (2 electrons), the whole 3d row (10), then 3 elements into the 4p block.
- So As = [Ar] 4s² 3d¹⁰ 4p³.
- Tungsten: the core is [Xe]. In period 6 you pass 6s (2), the 4f row of lanthanides (14), then 4 elements into the 5d row (groups 3 to 6).
- So W = [Xe] 6s² 4f¹⁴ 5d⁴.
As: [Ar] 4s² 3d¹⁰ 4p³; W: [Xe] 6s² 4f¹⁴ 5d⁴. (Count check for W: 54 + 2 + 14 + 4 = 74 ✓)
Worked exampleExample 2: Explaining an ionization energy exception
Phosphorus has a higher first ionization energy (1012 kJ/mol) than sulfur (1000 kJ/mol), even though sulfur has one more proton. Explain using box diagrams.
- P: [Ne] 3s² 3p³, with 3p boxes [↑][↑][↑]: every 3p electron is alone in its orbital.
- S: [Ne] 3s² 3p⁴, with 3p boxes [↑↓][↑][↑]: one orbital holds a pair.
- The paired electrons repel each other, which raises the energy of one of them, so it is easier to remove.
Sulfur's paired 3p electron is removed more easily because of electron-electron repulsion in the doubly occupied orbital, outweighing the extra proton.
Worked exampleExample 3: Using successive ionization energies
An unknown period 3 element has successive ionization energies (kJ/mol) of 578, 1817, 2745 and 11 577. Identify the element.
- Look for the big jump: from 2745 to 11 577, after the third electron.
- So the element has 3 valence electrons, and the fourth electron comes from a full inner level.
- The period 3 element with 3 valence electrons ([Ne] 3s² 3p¹) is in group 13.
Aluminium, which forms Al³⁺.
Just for funYtterby, a small village in Sweden, has four elements named after it: yttrium, ytterbium, terbium and erbium. All were found in minerals from one quarry there. Few places on Earth can claim even one.
Hands-on activityBuild your own block periodic table
You need: a large sheet of paper, a ruler, four coloured pencils (or plain shading patterns), and a printed or online periodic table to check against.
- Draw a grid of 18 columns and 7 rows, then a separate two rows of 14 cells underneath for the f block.
- Shade the s block, p block, d block and f block in different colours or patterns.
- Write the valence configuration pattern at the top of each block: s block: ns¹ or ns²; p block: ns² np¹ to ns² np⁶; d block: (n − 1)d¹ to (n − 1)d¹⁰; f block: (n − 2)f¹ to (n − 2)f¹⁴.
- Choose 6 elements you meet in daily life (for example: sodium in salt, calcium in milk, iron in a frying pan, copper in wiring, neodymium in earbud magnets, chlorine in pool water). Place each in your table and write its condensed configuration beside it.
- For each, write one property that matches its block.
What to look for: sodium and calcium (s block: reactive, form Na⁺ and Ca²⁺); iron and copper (d block: several ion charges, coloured compounds); chlorine (p block: gains one electron to form Cl⁻); neodymium (f block: strong magnets). Check each configuration's electron count against the atomic number.
Your turn
1In which block is each element: Sr, Co, Sb, U?
Sr: s; Co: d; Sb: p; U: f (actinide).
2Write the valence configuration shared by all group 17 elements.
3Use the table to write the condensed configuration of zirconium (period 5, group 4).
4Why is the d block 10 columns wide?
A d sublevel has 5 orbitals × 2 electrons = 10 electrons.
5Explain why beryllium has a higher first ionization energy than boron.
Boron's outer electron is in a 2p orbital, which is higher in energy and shielded by the 2s electrons, so it is easier to remove than beryllium's 2s electron.
6Give two characteristic properties of transition metals and explain one using electron configurations.
Any two: several ion charges, coloured compounds, paramagnetism, catalytic activity, high melting points. Example: several ion charges because the 4s and 3d electrons are close in energy, so different numbers can be lost.
7The successive IEs of an element are 496, 4562, 6910 kJ/mol. How many valence electrons does it have?
The big jump is after the first: 1 valence electron (it is sodium, group 1).
More practice: warm-up
1Which block contains the noble gases (except helium)?
2Which sublevel is filling in the lanthanides?
3What charge do group 2 metals form?
4Does atomic radius increase or decrease across a period?
5In which block are the most reactive metals?
More practice: on your own
1Write the condensed configuration of lead (period 6, group 14).
2Explain why the halogens all form 1− ions.
They all have ns² np⁵, one electron short of a full ns² np⁶ configuration, so each gains one electron.
3Explain the dip in ionization energy from magnesium (738) to aluminium (578).
Aluminium's outer electron is the first 3p electron, higher in energy and shielded by 3s, so it is easier to remove than magnesium's 3s electron.
4Why are lanthanides hard to separate from one another?
Their differences are in the inner 4f sublevel; their outer (6s, 5d) electrons are similar, so their chemical properties are very similar.
5Predict which element in each pair has the higher first IE and give the reason: (a) K or Ca (b) Ca or Ba.
(a) Ca: same level, higher Zeff across the period. (b) Ca: Ba's valence electron is in a higher level (6s), farther from the nucleus.
Challenge
1Element X has IE₁ to IE₅ of 1086, 2353, 4620, 6223 and 37 831 kJ/mol. Identify the group of X and suggest the element if it is in period 2.
The huge jump is after the 4th electron, so X has 4 valence electrons: group 14. In period 2 that is carbon (1s² 2s² 2p²); its IE₁ of 1086 kJ/mol matches the period 2 graph.
2The second ionization energy of fluorine (3374 kJ/mol) is slightly lower than that of oxygen (3388 kJ/mol). Explain, using the configurations of O⁺ and F⁺.
O⁺ is 1s² 2s² 2p³ (three unpaired 2p electrons, like nitrogen). F⁺ is 1s² 2s² 2p⁴ (one paired orbital, like oxygen). Removing an electron from F⁺ means removing a paired electron, helped by pairing repulsion, so IE₂(F) is slightly lower than IE₂(O) despite fluorine's larger nuclear charge.
3Element 117 (tennessine) has been made in laboratories. Predict its block, group and valence configuration.
It is in period 7, group 17, the p block, with valence configuration 7s² 7p⁵ (core [Rn] 5f¹⁴ 6d¹⁰).
Check your understandingQuiz
1. Which sublevel receives the last electron in elements of the d block of period 5?
2. What is the valence configuration of the group 16 elements?
3. Why is the first ionization energy of oxygen lower than that of nitrogen?
4. Which property is characteristic of many transition-metal compounds?
5. An element's successive IEs (kJ/mol) are 738, 1451, 7733. Which group is it in?
6. How many elements are in the f block in one period?
For parents and teachersBig idea (C3.3): the periodic table's shape comes from electron configurations. An element's block tells you which sublevel is filling, and its position tells you its valence configuration, which in turn explains its properties and the trends from Grade 11.
How to help: point to random elements on a periodic table and ask your teen for the block and condensed configuration. Ask "why" for each trend; the answer should mention Zeff, distance, or (for exceptions) sublevels and pairing.
Common difficulties:
- Using n for the d block instead of n − 1 (period 4 fills 3d, not 4d).
- Forgetting the 4f¹⁴ in period 6 configurations after the lanthanides.
- Explaining exceptions only by "half-filled is stable" without describing pairing repulsion or the higher energy of p electrons.