D. Trigonometric Functions · Sinusoidal FunctionsTransformations III: Horizontal Translations and Phase Shift (d)
D2.5 D2.6 D2.7About 70 minutes
Learning goals- I can explain how the parameter d in y = sin(x − d) and y = cos(x − d) changes the graph.
- I can find the phase shift of y = a sin(k(x − d)) + c, factoring k out when needed.
- I can sketch a graph with a phase shift using key points.
- I can explain why a sinusoidal graph can be written with more than one phase shift.
Words to know
horizontal translation
Sliding a graph left or right without changing its shape.
phase shift
The horizontal translation of a sinusoidal function: d in y = a sin(k(x − d)) + c. Right if d > 0, left if d < 0.
factored form
Writing the inside of the function as k(x − d), for example 2x − 60° = 2(x − 30°), so the phase shift can be read directly.
Same wave, later start
Two friends board the same Ferris wheel, one car apart. Their height graphs have exactly the same shape and the same period. The only difference is when things happen: the second friend reaches the top a few seconds later. On a graph, that is a horizontal translation. For sinusoidal functions it has a special name: the phase shift.
What d does
In y = sin(x − d), the graph of y = sin x is translated d units to the right (or |d| units to the left if d is negative).
Why does a minus sign mean right? The maximum of sine happens when its input is 90°. For y = sin(x − 60°) the input is x − 60°, so the maximum happens when x − 60° = 90°, that is, at x = 150°, which is 60° to the right of 90°. Everything happens 60° later.
Mapping rule: (x, y) → (x + d, y)
- y = sin(x − 60°): d = 60, shift 60° right.
- y = cos(x + 45°) = cos(x − (−45°)): d = −45, shift 45° left.
This matches Grade 10, where y = (x − h)² was y = x² moved h units right.
y = sin(x − 60°) (solid) is y = sin x (dashed) translated 60° to the right. Every key point is 60° later.Worked exampleExample 1: Sketching y = sin(x − 60°)
List the key points of one cycle of y = sin(x − 60°).
- d = 60: add 60° to each x-value of the sine key points.
- (0°, 0) → (60°, 0); (90°, 1) → (150°, 1); (180°, 0) → (240°, 0); (270°, −1) → (330°, −1); (360°, 0) → (420°, 0).
- The period (360°), amplitude (1) and axis (y = 0) do not change.
(60°, 0), (150°, 1), (240°, 0), (330°, −1), (420°, 0)
Worked exampleExample 2: A shift to the left
Sketch one cycle of y = cos(x + 45°).
- Rewrite: x + 45° = x − (−45°), so d = −45: shift 45° left.
- Subtract 45° from each x-value of the cosine key points (0°, 1), (90°, 0), (180°, −1), (270°, 0), (360°, 1):
- (−45°, 1), (45°, 0), (135°, −1), (225°, 0), (315°, 1).
(−45°, 1), (45°, 0), (135°, −1), (225°, 0), (315°, 1)
Watch out when k is not 1
In y = sin(2x − 60°) it is tempting to say "shift 60° right". That is wrong. The phase shift is d in k(x − d), so first factor out k:
2x − 60° = 2(x − 30°)
So y = sin(2x − 60°) = sin(2(x − 30°)): period 180°, phase shift 30° right.
The full mapping rule for y = a sin(k(x − d)) + c is
(x, y) → (x/k + d, ay + c)
Divide by k first, then add d.
Worked exampleExample 3: Factoring to find the phase shift
Find the period and phase shift of y = sin(2x − 60°) and list the key points of one cycle.
- Factor: y = sin(2(x − 30°)). k = 2, d = 30.
- Period 360° ÷ 2 = 180°. Phase shift 30° right.
- Apply (x, y) → (x/2 + 30°, y): (0°, 0) → (30°, 0); (90°, 1) → (75°, 1); (180°, 0) → (120°, 0); (270°, −1) → (165°, −1); (360°, 0) → (210°, 0).
- Check one point in the original equation: x = 75° gives sin(150° − 60°) = sin 90° = 1 ✓.
Period 180°, phase shift 30° right; key points (30°, 0), (75°, 1), (120°, 0), (165°, −1), (210°, 0).
The correct graph of y = sin(2x − 60°) = sin(2(x − 30°)) (solid) starts its cycle at 30°. The dashed graph shows the common mistake of shifting 60°.More than one right answer
Shifting a sine wave by one full period lands it on itself. So d and d ± 360° (or, in general, d plus or minus any multiple of the period) give the same graph. For example,
sin(x − 30°) = sin(x + 330°)
And since cosine is sine shifted 90° left, any sinusoidal graph can be written as either a sine or a cosine:
cos x = sin(x + 90°) and sin x = cos(x − 90°)
When you write equations later in this unit, there will usually be several correct answers. Pick the one with the simplest phase shift.
Worked exampleExample 4: Same graph, different equations
Show that y = sin(x − 90°) and y = −cos x have the same graph.
- Key points of y = sin(x − 90°): add 90° to each sine key point: (90°, 0), (180°, 1), (270°, 0), (360°, −1), (450°, 0). Since the graph repeats every 360°, the point (360°, −1) also gives (0°, −1).
- Key points of y = −cos x: (0°, −1), (90°, 0), (180°, 1), (270°, 0), (360°, −1).
- Both graphs pass through (0°, −1), (90°, 0), (180°, 1), (270°, 0) and (360°, −1), and both have period 360°, so they are the same.
Just for funPhase shift is the math name for being fashionably late. The graph of y = sin(x − 30°) does everything y = sin x does, just 30° later, and it never apologizes.
Hands-on activityDo "the wave" at home
You need: 3 or 4 people, chairs in a row and a timer (or someone counting seconds).
- Everyone sits. The first person stands up and sits down at a steady pace: up for 2 seconds, down for 2 seconds, over and over (period 4 s).
- The second person does exactly the same thing, but starts 1 second later. The third starts 1 second after the second, and so on.
- Watch from the side: a wave travels along the row!
- Sketch the graph of head height against time for person 1 and for person 3 on the same axes.
- Answer: What is the period of each graph? How are the graphs of person 1 and person 3 related? Which parameter, a, k, d or c, describes the difference?
What to look for: every graph has the same shape, period (4 s) and amplitude. Person 3's graph is person 1's graph translated 2 seconds to the right: a phase shift, d = 2. (Standing and sitting give a graph with flat tops, so it is periodic but only roughly sinusoidal: a nice reminder from the first lesson.)
Your turn
1State the phase shift of y = sin(x − 40°).
2State the phase shift of y = cos(x + 30°).
3List the key points of one cycle of y = sin(x + 90°). Which parent function has the same graph?
Subtract 90°: (−90°, 0), (0°, 1), (90°, 0), (180°, −1), (270°, 0). This is the graph of y = cos x.
4Find the period and phase shift of y = sin(3x − 90°).
Factor: sin(3(x − 30°)). Period 120°, phase shift 30° right.
5Find the period and phase shift of y = cos(2x + 180°).
Factor: cos(2(x + 90°)). Period 180°, phase shift 90° left.
6Write the equation of y = sin x translated 45° right and 2 units up.
7Where does the point (0°, 1) on y = cos x go under y = cos(x − 120°)?
More practice: warm-up
1Describe the phase shift of y = sin(x − 25°).
2Describe the phase shift of y = cos(x + 10°).
3Write the equation of y = sin x translated 70° right.
4Does the phase shift change the period?
No. It only slides the graph.
5Does the phase shift change the range?
No. The maximum and minimum values stay the same.
More practice: on your own
1List the key points of one cycle of y = cos(x − 60°).
Add 60°: (60°, 1), (150°, 0), (240°, −1), (330°, 0), (420°, 1).
2Find the period and phase shift of y = sin(4x + 120°).
Factor: sin(4(x + 30°)). Period 90°, phase shift 30° left.
3For y = 2 sin(x − 30°) + 1, find the maximum value and the first x ≥ 0° where it happens.
Max = 1 + 2 = 3. It happens when x − 30° = 90°, so x = 120°.
4Give two different values of d, one positive and one negative, for which y = sin(x − d) has the same graph as y = sin(x − 100°).
d = 100 and d = −260 (100 − 360 = −260). So y = sin(x + 260°) is the same graph.
5Explain why sin(x − 360°) = sin x for every x.
Translating the graph 360° right moves it exactly one period, so every cycle lands on the next one. (On the unit circle, x − 360° and x are coterminal.)
Challenge
1Find the smallest positive d for which y = cos(x − d) has the same graph as y = sin x.
cos x has its maximum at 0°; sin x has its maximum at 90°. Shift cosine 90° right: d = 90, so sin x = cos(x − 90°).
2Write y = −sin x as a sine function with a phase shift (no negative a).
Shifting y = sin x by half a period turns it upside down: y = sin(x − 180°) (or y = sin(x + 180°)).
3Find the period and phase shift of y = sin(0.5x − 45°), and list the key points of one cycle.
Factor: 0.5x − 45° = 0.5(x − 90°). Period 360° ÷ 0.5 = 720°, shift 90° right. (x, y) → (2x + 90°, y): (90°, 0), (270°, 1), (450°, 0), (630°, −1), (810°, 0).
Check your understandingQuiz
1. What is the phase shift of y = sin(x + 50°)?
2. What is the phase shift of y = cos(3x − 120°)?
3. Under y = sin(x − 30°), where does the point (90°, 1) of y = sin x go?
4. Which equation translates y = cos x by 60° to the right?
5. Which function has the same graph as y = cos x?
6. Which of these does the phase shift d change?
For parents and teachersBig idea: This lesson completes the four parameters for D2.5 to D2.7 with d, the phase shift. The two big ideas are "minus means right" and factor out k before reading d.
How to help: Ask your teen to explain why y = sin(x − 60°) reaches its maximum at 150° ("the inside has to be 90°"). For any equation with a number in front of x, ask, "Did you factor?"
Common difficulties:
- Shifting the wrong way: (x − 60°) means right, (x + 60°) means left.
- Not factoring: sin(2x − 60°) shifts 30°, not 60°.
- Applying the mapping rule in the wrong order. Divide by k first, then add d.
- Being surprised by multiple correct answers. Different phase shifts that differ by a full period (or sine versus cosine) can describe the same graph.